User blog:ArbitraryNumbers/Lifting Bikini Bottom

Intro
I was requested to calc the lifting strength required to lift Bikini Bottom.

I will be using this calc for reference.

https://vsbattles.wikia.com/wiki/User_blog:ArbitraryNumbers/Destroying_Bikini_Bottom_(Redone)

Calc
One small building is 4382.5 cubic centimeters.

One large building is 20,600 cubic centimeters.

For the low end weight, we'll use the smaller picture of Bikini Bottom, which has 13 small buildings and 4 large ones.

Density of steel is 7 g/cm^2

4,382.5 * 13 * 7.7 g/cm^3 = 438,688.25

20,600 * 4 * 7.7 g/cm^3 = 634,480

634480 + 438688.25 = = 1073168.25 grams, or 1073.16825 kilograms.

Now that would normally be Class 1, but we're going to need to take into account the buoyant forces first.

First for the force of buoyancy:

Bouyancy = Volume * Density of liquid * gravity

The total combined volume of the city would be 139372.5 cubic centimeters, or 0.1393725 cubic meters.

The density of water is 997 kg/m^3

Gravity is 9.8 m/s

0.1393725 * 997 * 9.8 = 1361.7529485 newtons

Now for the force of gravity on Bikini Bottom:

1073.16825 * 9.8 = 10517.04885 newtons

10517.04885 - 1361.7529485 = 9,155.3 newtons.

One newton is equal to 9.81 kilograms.

9,155.3 / 9.81 = 934 kilograms, which is Class 1